What are the solutions to the equation quadraticformula x^2-x-20=0 ?

The solutions to the equation quadraticformula x^2-x-20=0 are x=5,x=-4

Find the zeros of quadraticformula x^2-x-20=0

The zeros of quadraticformula x^2-x-20=0 are x=5,x=-4

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x^{2} - x - 20 = 0

x = 5, x = - 4

Solution steps

x^{2} - x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 20) = 9

x_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 1}

x = \frac{- ( - 1 ) + 9}{2 \cdot 1} : 5

x = \frac{- ( - 1 ) - 9}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 5, x = - 4

x^{2} - 25 x + 156 = 0

6 (x - 1) = x^{2} + x

2 = x^{2} - 3 x - 8

4 = \frac{4}{3} (x - 6) 34 (x - 6)

t, S = \frac{1}{2} a t^{2}

What are the solutions to the equation quadraticformula x^2-x-20=0 ?
The solutions to the equation quadraticformula x^2-x-20=0 are x=5,x=-4
Find the zeros of quadraticformula x^2-x-20=0
The zeros of quadraticformula x^2-x-20=0 are x=5,x=-4