What are the solutions to the equation 2=x^2-3x-8 ?

The solutions to the equation 2=x^2-3x-8 are x=5,x=-2

Find the zeros of 2=x^2-3x-8

The zeros of 2=x^2-3x-8 are x=5,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 = x^{2} - 3 x - 8

x = 5, x = - 2

Solution steps

2 = x^{2} - 3 x - 8

Switch sides

x^{2} - 3 x - 8 = 2

Move

2

to the left side

x^{2} - 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 10) = 7

x_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 1}

x = \frac{- ( - 3 ) + 7}{2 \cdot 1} : 5

x = \frac{- ( - 3 ) - 7}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 5, x = - 2

4 = \frac{4}{3} (x - 6) 34 (x - 6)

t, S = \frac{1}{2} a t^{2}

- 9 x^{2} + 24 x - 16 = 0

y, 4 y^{2} - 3 x = - 4 (x - 5)

(3 x + 7)^{2} - 25 = 0

What are the solutions to the equation 2=x^2-3x-8 ?
The solutions to the equation 2=x^2-3x-8 are x=5,x=-2
Find the zeros of 2=x^2-3x-8
The zeros of 2=x^2-3x-8 are x=5,x=-2