What are the solutions to the equation -9x^2+24x-16=0 ?

The solutions to the equation -9x^2+24x-16=0 are x= 4/3

Find the zeros of -9x^2+24x-16=0

The zeros of -9x^2+24x-16=0 are x= 4/3

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- 9 x^{2} + 24 x - 16 = 0

x = \frac{4}{3}

Decimal Notation

x = 1.33333 \dots

Solution steps

- 9 x^{2} + 24 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 ( - 9 ) ( - 16 )}{2 ( - 9 )}

2 4^{2} - 4 (- 9) (- 16) = 0

x_{1, 2} = \frac{- 24 \pm 0}{2 ( - 9 )}

x = \frac{- 24}{2 ( - 9 )}

\frac{- 24}{2 ( - 9 )} = \frac{4}{3}

x = \frac{4}{3}

The solution to the quadratic equation is:

x = \frac{4}{3}

y, 4 y^{2} - 3 x = - 4 (x - 5)

(3 x + 7)^{2} - 25 = 0

3 x^{2} + 7 x - 6 = 0

y, x = 2 - y^{2}

9 n^{2} + 3 = 67

What are the solutions to the equation -9x^2+24x-16=0 ?
The solutions to the equation -9x^2+24x-16=0 are x= 4/3
Find the zeros of -9x^2+24x-16=0
The zeros of -9x^2+24x-16=0 are x= 4/3