What are the solutions to the equation 4= 4/3 (x-6)34(x-6) ?

The solutions to the equation 4= 4/3 (x-6)34(x-6) are x=sqrt(3/34)+6,x=-sqrt(3/34)+6

Find the zeros of 4= 4/3 (x-6)34(x-6)

The zeros of 4= 4/3 (x-6)34(x-6) are x=sqrt(3/34)+6,x=-sqrt(3/34)+6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 = \frac{4}{3} (x - 6) 34 (x - 6)

x = \frac{3}{34} + 6, x = - \frac{3}{34} + 6

Decimal Notation

x = 6.29704 \dots, x = 5.70295 \dots

Solution steps

4 = \frac{4}{3} (x - 6) \cdot 34 (x - 6)

Switch sides

\frac{4}{3} (x - 6) \cdot 34 (x - 6) = 4

Simplify

\frac{136}{3} (x - 6)^{2} = 4

Multiply both sides by

3

3 \cdot \frac{136}{3} (x - 6)^{2} = 4 \cdot 3

136 (x - 6)^{2} = 12

Divide both sides by

136

\frac{136 ( x - 6 ) ^{2}}{136} = \frac{12}{136}

(x - 6)^{2} = \frac{3}{34}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 6 = \frac{3}{34} : x = \frac{3}{34} + 6

Solve

x - 6 = - \frac{3}{34} : x = - \frac{3}{34} + 6

The solutions to the quadratic equation are:

x = \frac{3}{34} + 6, x = - \frac{3}{34} + 6

t, S = \frac{1}{2} a t^{2}

- 9 x^{2} + 24 x - 16 = 0

y, 4 y^{2} - 3 x = - 4 (x - 5)

(3 x + 7)^{2} - 25 = 0

3 x^{2} + 7 x - 6 = 0

What are the solutions to the equation 4= 4/3 (x-6)34(x-6) ?
The solutions to the equation 4= 4/3 (x-6)34(x-6) are x=sqrt(3/34)+6,x=-sqrt(3/34)+6
Find the zeros of 4= 4/3 (x-6)34(x-6)
The zeros of 4= 4/3 (x-6)34(x-6) are x=sqrt(3/34)+6,x=-sqrt(3/34)+6