What are the solutions to the equation completesquare 3x^2+7x-6=0 ?

The solutions to the equation completesquare 3x^2+7x-6=0 are x= 2/3 ,x=-3

Find the zeros of completesquare 3x^2+7x-6=0

The zeros of completesquare 3x^2+7x-6=0 are x= 2/3 ,x=-3

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3 x^{2} + 7 x - 6 = 0

x = \frac{2}{3}, x = - 3

Decimal Notation

x = 0.66666 \dots, x = - 3

Solution steps

3 x^{2} + 7 x - 6 = 0

Move

6

to the right side

3 x^{2} + 7 x = 6

Divide both sides by

3

\frac{3 x ^{2} + 7 x}{3} = \frac{6}{3}

x^{2} + \frac{7 x}{3} = 2

Rewrite in the form

(x + a)^{2} = b

(x + \frac{7}{6})^{2} = \frac{121}{36}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{7}{6} = \frac{121}{36} : x = \frac{2}{3}

Solve

x + \frac{7}{6} = - \frac{121}{36} : x = - 3

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 3

y, x = 2 - y^{2}

9 n^{2} + 3 = 67

y, x^{2} + (y - 3)^{2} = 9

2 x^{2} + 9 x - 15 = 0

2 n^{2} = 12 - 5 n

What are the solutions to the equation completesquare 3x^2+7x-6=0 ?
The solutions to the equation completesquare 3x^2+7x-6=0 are x= 2/3 ,x=-3
Find the zeros of completesquare 3x^2+7x-6=0
The zeros of completesquare 3x^2+7x-6=0 are x= 2/3 ,x=-3