What are the solutions to the equation c^2-9c+20=0 ?

The solutions to the equation c^2-9c+20=0 are c=5,c=4

Find the zeros of c^2-9c+20=0

The zeros of c^2-9c+20=0 are c=5,c=4

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c^{2} - 9 c + 20 = 0

c = 5, c = 4

Solution steps

c^{2} - 9 c + 20 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 20 = 1

c_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 1}, c_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 1}

c = \frac{- ( - 9 ) + 1}{2 \cdot 1} : 5

c = \frac{- ( - 9 ) - 1}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

c = 5, c = 4

x^{2} + (3 x)^{2} = 16

2 x^{2} + 5 x = 25

x^{2} = 2 x + 7

(x + 3) (x - 1) = - 3 x + 4

- x^{2} + 2 x - 15 = 0

What are the solutions to the equation c^2-9c+20=0 ?
The solutions to the equation c^2-9c+20=0 are c=5,c=4
Find the zeros of c^2-9c+20=0
The zeros of c^2-9c+20=0 are c=5,c=4