What are the solutions to the equation 2z^2-5z+2=0 ?

The solutions to the equation 2z^2-5z+2=0 are z=2,z= 1/2

Find the zeros of 2z^2-5z+2=0

The zeros of 2z^2-5z+2=0 are z=2,z= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 z^{2} - 5 z + 2 = 0

z = 2, z = \frac{1}{2}

Decimal Notation

z = 2, z = 0.5

Solution steps

2 z^{2} - 5 z + 2 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 \cdot 2 = 3

z_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 2}

Separate the solutions

z_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 2}, z_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 2}

z = \frac{- ( - 5 ) + 3}{2 \cdot 2} : 2

z = \frac{- ( - 5 ) - 3}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

z = 2, z = \frac{1}{2}

29 x^{2} - 3 = 8 - 20 x^{2}

y, x^{2} - y^{2} = x

4 x^{2} + 2 x - 9 = (x - 2) (x - 9)

32 x^{2} + 32 = 0

(x + 4)^{2} = 9 x + 22

What are the solutions to the equation 2z^2-5z+2=0 ?
The solutions to the equation 2z^2-5z+2=0 are z=2,z= 1/2
Find the zeros of 2z^2-5z+2=0
The zeros of 2z^2-5z+2=0 are z=2,z= 1/2