What are the solutions to the equation 8x^2+3=0 ?

The solutions to the equation 8x^2+3=0 are x=(sqrt(3))/(2sqrt(2))i,x=-(sqrt(3))/(2sqrt(2))i

Find the zeros of 8x^2+3=0

The zeros of 8x^2+3=0 are x=(sqrt(3))/(2sqrt(2))i,x=-(sqrt(3))/(2sqrt(2))i

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8 x^{2} + 3 = 0

x = \frac{3}{2 2} i, x = - \frac{3}{2 2} i

Solution steps

8 x^{2} + 3 = 0

Move

3

to the right side

8 x^{2} = - 3

Divide both sides by

8

x^{2} = - \frac{3}{8}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{3}{8}, x = - - \frac{3}{8}

- \frac{3}{8} = \frac{3}{2 2} i

- - \frac{3}{8} = - \frac{3}{2 2} i

x = \frac{3}{2 2} i, x = - \frac{3}{2 2} i

9 x^{2} + 9 x = 7

196 q - q^{2} = 0

3 x^{2} = 14 x + 5

1 xx + 15 x + 515 = 0

x^{2} - 8 x = 15

What are the solutions to the equation 8x^2+3=0 ?
The solutions to the equation 8x^2+3=0 are x=(sqrt(3))/(2sqrt(2))i,x=-(sqrt(3))/(2sqrt(2))i
Find the zeros of 8x^2+3=0
The zeros of 8x^2+3=0 are x=(sqrt(3))/(2sqrt(2))i,x=-(sqrt(3))/(2sqrt(2))i