What are the solutions to the equation 196q-q^2=0 ?

The solutions to the equation 196q-q^2=0 are q=0,q=196

Find the zeros of 196q-q^2=0

The zeros of 196q-q^2=0 are q=0,q=196

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196 q - q^{2} = 0

q = 0, q = 196

Solution steps

196 q - q^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- q^{2} + 196 q = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 196 \pm 19 6 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

19 6^{2} - 4 (- 1) \cdot 0 = 196

q_{1, 2} = \frac{- 196 \pm 196}{2 ( - 1 )}

Separate the solutions

q_{1} = \frac{- 196 + 196}{2 ( - 1 )}, q_{2} = \frac{- 196 - 196}{2 ( - 1 )}

q = \frac{- 196 + 196}{2 ( - 1 )} : 0

q = \frac{- 196 - 196}{2 ( - 1 )} : 196

The solutions to the quadratic equation are:

q = 0, q = 196

3 x^{2} = 14 x + 5

1 xx + 15 x + 515 = 0

x^{2} - 8 x = 15

3 x^{2} - 4 = - 5 x

3 d^{2} - 4 d = 0

What are the solutions to the equation 196q-q^2=0 ?
The solutions to the equation 196q-q^2=0 are q=0,q=196
Find the zeros of 196q-q^2=0
The zeros of 196q-q^2=0 are q=0,q=196