What are the solutions to the equation 1+10x-0.9x^2=0 ?

The solutions to the equation 1+10x-0.9x^2=0 are x=-(-50+sqrt(2590))/9 ,x=(50+sqrt(2590))/9

Find the zeros of 1+10x-0.9x^2=0

The zeros of 1+10x-0.9x^2=0 are x=-(-50+sqrt(2590))/9 ,x=(50+sqrt(2590))/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1 + 10 x - 0.9 x^{2} = 0

x = - \frac{- 50 + 2590}{9}, x = \frac{50 + 2590}{9}

Decimal Notation

x = - 0.09911 \dots, x = 11.21022 \dots

Solution steps

1 + 10 x - 0.9 x^{2} = 0

Multiply both sides by

10

10 + 100 x - 9 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 9 x^{2} + 100 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 100 \pm 10 0 ^{2} - 4 ( - 9 ) \cdot 10}{2 ( - 9 )}

10 0^{2} - 4 (- 9) \cdot 10 = 22590

x_{1, 2} = \frac{- 100 \pm 2 2590}{2 ( - 9 )}

Separate the solutions

x_{1} = \frac{- 100 + 2 2590}{2 ( - 9 )}, x_{2} = \frac{- 100 - 2 2590}{2 ( - 9 )}

x = \frac{- 100 + 2 2590}{2 ( - 9 )} : - \frac{- 50 + 2590}{9}

x = \frac{- 100 - 2 2590}{2 ( - 9 )} : \frac{50 + 2590}{9}

The solutions to the quadratic equation are:

x = - \frac{- 50 + 2590}{9}, x = \frac{50 + 2590}{9}

x^{2} + 5 = 8

4 w^{2} - 7 w + 6 = 5

(5 - x)^{2} = 0

- 2 s^{2} + 8 s - 4 = 0

x, x^{2} - 3 x + 2 = y

What are the solutions to the equation 1+10x-0.9x^2=0 ?
The solutions to the equation 1+10x-0.9x^2=0 are x=-(-50+sqrt(2590))/9 ,x=(50+sqrt(2590))/9
Find the zeros of 1+10x-0.9x^2=0
The zeros of 1+10x-0.9x^2=0 are x=-(-50+sqrt(2590))/9 ,x=(50+sqrt(2590))/9