What are the solutions to the equation 24=-0.5x^2+3.2x+22 ?

The solutions to the equation 24=-0.5x^2+3.2x+22 are x=(2(8-sqrt(39)))/5 ,x=(2(8+sqrt(39)))/5

Find the zeros of 24=-0.5x^2+3.2x+22

The zeros of 24=-0.5x^2+3.2x+22 are x=(2(8-sqrt(39)))/5 ,x=(2(8+sqrt(39)))/5

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24 = - 0.5 x^{2} + 3.2 x + 22

x = \frac{2 ( 8 - 39 )}{5}, x = \frac{2 ( 8 + 39 )}{5}

Decimal Notation

x = 0.70200 \dots, x = 5.69799 \dots

Solution steps

24 = - 0.5 x^{2} + 3.2 x + 22

Multiply both sides by

10

240 = - 5 x^{2} + 32 x + 220

Switch sides

- 5 x^{2} + 32 x + 220 = 240

Move

240

to the left side

- 5 x^{2} + 32 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 ( - 5 ) ( - 20 )}{2 ( - 5 )}

3 2^{2} - 4 (- 5) (- 20) = 439

x_{1, 2} = \frac{- 32 \pm 4 39}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 32 + 4 39}{2 ( - 5 )}, x_{2} = \frac{- 32 - 4 39}{2 ( - 5 )}

x = \frac{- 32 + 4 39}{2 ( - 5 )} : \frac{2 ( 8 - 39 )}{5}

x = \frac{- 32 - 4 39}{2 ( - 5 )} : \frac{2 ( 8 + 39 )}{5}

The solutions to the quadratic equation are:

x = \frac{2 ( 8 - 39 )}{5}, x = \frac{2 ( 8 + 39 )}{5}

m^{2} - 6 m + 2 = 0

- 3 x^{2} - 42 x - 375 = - 12

(x - 6) (x - 10) = - 4

Q^{2} - 3092.8 Q + 120000 = 0

- 3 x^{2} - 18 x + 2 = 0

What are the solutions to the equation 24=-0.5x^2+3.2x+22 ?
The solutions to the equation 24=-0.5x^2+3.2x+22 are x=(2(8-sqrt(39)))/5 ,x=(2(8+sqrt(39)))/5
Find the zeros of 24=-0.5x^2+3.2x+22
The zeros of 24=-0.5x^2+3.2x+22 are x=(2(8-sqrt(39)))/5 ,x=(2(8+sqrt(39)))/5