What are the solutions to the equation k^2-10k+25=0 ?

The solutions to the equation k^2-10k+25=0 are k=5

Find the zeros of k^2-10k+25=0

The zeros of k^2-10k+25=0 are k=5

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k^{2} - 10 k + 25 = 0

k = 5

Solution steps

k^{2} - 10 k + 25 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 25 = 0

k_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 1}

k = \frac{- ( - 10 )}{2 \cdot 1}

\frac{- ( - 10 )}{2 \cdot 1} = 5

k = 5

The solution to the quadratic equation is:

k = 5

x^{2} - 841 = 0

6 x^{2} - 53 x = 9

\frac{b - 2 x ^{2}}{a} = 5

x^{2} = 8 x - 15

(3 x - 5) (4 - 2 x) = 0

What are the solutions to the equation k^2-10k+25=0 ?
The solutions to the equation k^2-10k+25=0 are k=5
Find the zeros of k^2-10k+25=0
The zeros of k^2-10k+25=0 are k=5