What are the solutions to the equation quadraticformula x^2=8x-15 ?

The solutions to the equation quadraticformula x^2=8x-15 are x=5,x=3

Find the zeros of quadraticformula x^2=8x-15

The zeros of quadraticformula x^2=8x-15 are x=5,x=3

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x^{2} = 8 x - 15

x = 5, x = 3

Solution steps

x^{2} = 8 x - 15

Move

15

to the left side

x^{2} + 15 = 8 x

Move

8 x

to the left side

x^{2} + 15 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 8 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

x_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

x = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 5, x = 3

(3 x - 5) (4 - 2 x) = 0

x^{2} + 16 x + 56 = 0

12 x^{2} + 23 x - 24 = 0

5 (x - 3)^{2} = 30

2 m^{2} - 10 m + 12 = 0

What are the solutions to the equation quadraticformula x^2=8x-15 ?
The solutions to the equation quadraticformula x^2=8x-15 are x=5,x=3
Find the zeros of quadraticformula x^2=8x-15
The zeros of quadraticformula x^2=8x-15 are x=5,x=3