What are the solutions to the equation (3x-5)(4-2x)=0 ?

The solutions to the equation (3x-5)(4-2x)=0 are x= 5/3 ,x=2

Find the zeros of (3x-5)(4-2x)=0

The zeros of (3x-5)(4-2x)=0 are x= 5/3 ,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(3 x - 5) (4 - 2 x) = 0

x = \frac{5}{3}, x = 2

Decimal Notation

x = 1.66666 \dots, x = 2

Solution steps

(3 x - 5) (4 - 2 x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 5 = 0 or 4 - 2 x = 0

Solve

3 x - 5 = 0 : x = \frac{5}{3}

Solve

4 - 2 x = 0 : x = 2

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = 2

x^{2} + 16 x + 56 = 0

12 x^{2} + 23 x - 24 = 0

5 (x - 3)^{2} = 30

2 m^{2} - 10 m + 12 = 0

(2 x - 1) (x + 3) = 2 x

What are the solutions to the equation (3x-5)(4-2x)=0 ?
The solutions to the equation (3x-5)(4-2x)=0 are x= 5/3 ,x=2
Find the zeros of (3x-5)(4-2x)=0
The zeros of (3x-5)(4-2x)=0 are x= 5/3 ,x=2