What are the solutions to the equation (p^2-2p)/6 = p/2 ?

The solutions to the equation (p^2-2p)/6 = p/2 are p=5,p=0

Find the zeros of (p^2-2p)/6 = p/2

The zeros of (p^2-2p)/6 = p/2 are p=5,p=0

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\frac{p ^{2} - 2 p}{6} = \frac{p}{2}

p = 5, p = 0

Solution steps

\frac{p ^{2} - 2 p}{6} = \frac{p}{2}

Find Least Common Multiplier of

6, 2 : 6

Multiply by LCM=

6

\frac{p ^{2} - 2 p}{6} \cdot 6 = \frac{p}{2} \cdot 6

Simplify

p^{2} - 2 p = 3 p

Move

3 p

to the left side

p^{2} - 5 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 0 = 5

p_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 1}, p_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 1}

p = \frac{- ( - 5 ) + 5}{2 \cdot 1} : 5

p = \frac{- ( - 5 ) - 5}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

p = 5, p = 0

n^{2} + 15 n = - 43

7 x + x^{2} - 18 = 0

3 x^{2} + 2 x - 5 = 2 x^{2} - 2

(2 x - 3) (x + c) = a x^{2} + b x - 12

3 x^{2} + x - 2 = 0

What are the solutions to the equation (p^2-2p)/6 = p/2 ?
The solutions to the equation (p^2-2p)/6 = p/2 are p=5,p=0
Find the zeros of (p^2-2p)/6 = p/2
The zeros of (p^2-2p)/6 = p/2 are p=5,p=0