What are the solutions to the equation 25z^2-110z+121=16 ?

The solutions to the equation 25z^2-110z+121=16 are z=3,z= 7/5

Find the zeros of 25z^2-110z+121=16

The zeros of 25z^2-110z+121=16 are z=3,z= 7/5

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25 z^{2} - 110 z + 121 = 16

z = 3, z = \frac{7}{5}

Decimal Notation

z = 3, z = 1.4

Solution steps

25 z^{2} - 110 z + 121 = 16

Move

16

to the left side

25 z^{2} - 110 z + 105 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 110 ) \pm ( - 110 ) ^{2} - 4 \cdot 25 \cdot 105}{2 \cdot 25}

(- 110)^{2} - 4 \cdot 25 \cdot 105 = 40

z_{1, 2} = \frac{- ( - 110 ) \pm 40}{2 \cdot 25}

Separate the solutions

z_{1} = \frac{- ( - 110 ) + 40}{2 \cdot 25}, z_{2} = \frac{- ( - 110 ) - 40}{2 \cdot 25}

z = \frac{- ( - 110 ) + 40}{2 \cdot 25} : 3

z = \frac{- ( - 110 ) - 40}{2 \cdot 25} : \frac{7}{5}

The solutions to the quadratic equation are:

z = 3, z = \frac{7}{5}

x^{2} + 3 x + \frac{3}{2} = 0

- x^{2} + 1 = - 5 x^{2} + 4 x

x^{2} - 17 x + 4 = 0

3 x^{2} + 4 x = 8

5 x^{2} + 8 x - 17 = 0

What are the solutions to the equation 25z^2-110z+121=16 ?
The solutions to the equation 25z^2-110z+121=16 are z=3,z= 7/5
Find the zeros of 25z^2-110z+121=16
The zeros of 25z^2-110z+121=16 are z=3,z= 7/5