What are the solutions to the equation (3x)^2-5(3x)-14=0 ?

The solutions to the equation (3x)^2-5(3x)-14=0 are x= 7/3 ,x=-2/3

Find the zeros of (3x)^2-5(3x)-14=0

The zeros of (3x)^2-5(3x)-14=0 are x= 7/3 ,x=-2/3

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(3 x)^{2} - 5 (3 x) - 14 = 0

x = \frac{7}{3}, x = - \frac{2}{3}

Decimal Notation

x = 2.33333 \dots, x = - 0.66666 \dots

Solution steps

(3 x)^{2} - 5 (3 x) - 14 = 0

Expand

(3 x)^{2} - 5 (3 x) - 14 : 9 x^{2} - 15 x - 14

9 x^{2} - 15 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 9 ( - 14 )}{2 \cdot 9}

(- 15)^{2} - 4 \cdot 9 (- 14) = 27

x_{1, 2} = \frac{- ( - 15 ) \pm 27}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 27}{2 \cdot 9}, x_{2} = \frac{- ( - 15 ) - 27}{2 \cdot 9}

x = \frac{- ( - 15 ) + 27}{2 \cdot 9} : \frac{7}{3}

x = \frac{- ( - 15 ) - 27}{2 \cdot 9} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{7}{3}, x = - \frac{2}{3}

3000 = - 35 x^{2} + 1250 x - 6500

p^{2} - 1 p = 0

24 x^{2} + 28 x + 4 = 0

20 x^{2} - 5 = 0

x^{2} = 6 x - 66

What are the solutions to the equation (3x)^2-5(3x)-14=0 ?
The solutions to the equation (3x)^2-5(3x)-14=0 are x= 7/3 ,x=-2/3
Find the zeros of (3x)^2-5(3x)-14=0
The zeros of (3x)^2-5(3x)-14=0 are x= 7/3 ,x=-2/3