What are the solutions to the equation 7x^2+4x+4=8x+2 ?

The solutions to the equation 7x^2+4x+4=8x+2 are x= 2/7+i(sqrt(10))/7 ,x= 2/7-i(sqrt(10))/7

Find the zeros of 7x^2+4x+4=8x+2

The zeros of 7x^2+4x+4=8x+2 are x= 2/7+i(sqrt(10))/7 ,x= 2/7-i(sqrt(10))/7

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7 x^{2} + 4 x + 4 = 8 x + 2

x = \frac{2}{7} + i \frac{10}{7}, x = \frac{2}{7} - i \frac{10}{7}

Solution steps

7 x^{2} + 4 x + 4 = 8 x + 2

Move

2

to the left side

7 x^{2} + 4 x + 2 = 8 x

Move

8 x

to the left side

7 x^{2} - 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 7 \cdot 2}{2 \cdot 7}

Simplify

(- 4)^{2} - 4 \cdot 7 \cdot 2 : 210 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 10 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 10 i}{2 \cdot 7}, x_{2} = \frac{- ( - 4 ) - 2 10 i}{2 \cdot 7}

x = \frac{- ( - 4 ) + 2 10 i}{2 \cdot 7} : \frac{2}{7} + i \frac{10}{7}

x = \frac{- ( - 4 ) - 2 10 i}{2 \cdot 7} : \frac{2}{7} - i \frac{10}{7}

The solutions to the quadratic equation are:

x = \frac{2}{7} + i \frac{10}{7}, x = \frac{2}{7} - i \frac{10}{7}

x^{2} + 12 x - 20 = 8

55 x^{2} = 34 x + 21

x, 8 x^{2} - 4 x - 20 = 0

x^{2} + 21 x + 54 = 0

200 = 0.1 x^{2} + 2.155 x + 19.985

What are the solutions to the equation 7x^2+4x+4=8x+2 ?
The solutions to the equation 7x^2+4x+4=8x+2 are x= 2/7+i(sqrt(10))/7 ,x= 2/7-i(sqrt(10))/7
Find the zeros of 7x^2+4x+4=8x+2
The zeros of 7x^2+4x+4=8x+2 are x= 2/7+i(sqrt(10))/7 ,x= 2/7-i(sqrt(10))/7