What are the solutions to the equation 55x^2=34x+21 ?

The solutions to the equation 55x^2=34x+21 are x=1,x=-21/55

Find the zeros of 55x^2=34x+21

The zeros of 55x^2=34x+21 are x=1,x=-21/55

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55 x^{2} = 34 x + 21

x = 1, x = - \frac{21}{55}

Decimal Notation

x = 1, x = - 0.38181 \dots

Solution steps

55 x^{2} = 34 x + 21

Move

21

to the left side

55 x^{2} - 21 = 34 x

Move

34 x

to the left side

55 x^{2} - 21 - 34 x = 0

Write in the standard form

a x^{2} + b x + c = 0

55 x^{2} - 34 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 34 ) \pm ( - 34 ) ^{2} - 4 \cdot 55 ( - 21 )}{2 \cdot 55}

(- 34)^{2} - 4 \cdot 55 (- 21) = 76

x_{1, 2} = \frac{- ( - 34 ) \pm 76}{2 \cdot 55}

Separate the solutions

x_{1} = \frac{- ( - 34 ) + 76}{2 \cdot 55}, x_{2} = \frac{- ( - 34 ) - 76}{2 \cdot 55}

x = \frac{- ( - 34 ) + 76}{2 \cdot 55} : 1

x = \frac{- ( - 34 ) - 76}{2 \cdot 55} : - \frac{21}{55}

The solutions to the quadratic equation are:

x = 1, x = - \frac{21}{55}

x, 8 x^{2} - 4 x - 20 = 0

x^{2} + 21 x + 54 = 0

200 = 0.1 x^{2} + 2.155 x + 19.985

9 k^{2} + 21 = 25

(k - 1) x^{2} + (k + 4) x + 25 = 0, k \neq = 1

What are the solutions to the equation 55x^2=34x+21 ?
The solutions to the equation 55x^2=34x+21 are x=1,x=-21/55
Find the zeros of 55x^2=34x+21
The zeros of 55x^2=34x+21 are x=1,x=-21/55