What are the solutions to the equation 0.25x^2-2x+3=0 ?

The solutions to the equation 0.25x^2-2x+3=0 are x=6,x=2

Find the zeros of 0.25x^2-2x+3=0

The zeros of 0.25x^2-2x+3=0 are x=6,x=2

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0.25 x^{2} - 2 x + 3 = 0

x = 6, x = 2

Solution steps

0.25 x^{2} - 2 x + 3 = 0

Multiply both sides by

100

25 x^{2} - 200 x + 300 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 200 ) \pm ( - 200 ) ^{2} - 4 \cdot 25 \cdot 300}{2 \cdot 25}

(- 200)^{2} - 4 \cdot 25 \cdot 300 = 100

x_{1, 2} = \frac{- ( - 200 ) \pm 100}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- ( - 200 ) + 100}{2 \cdot 25}, x_{2} = \frac{- ( - 200 ) - 100}{2 \cdot 25}

x = \frac{- ( - 200 ) + 100}{2 \cdot 25} : 6

x = \frac{- ( - 200 ) - 100}{2 \cdot 25} : 2

The solutions to the quadratic equation are:

x = 6, x = 2

x^{2} + 12 x - 15 = 0

(2 w - 3) w = 44

x^{2} - b x + 5 = 0

125 a = 5 a^{2}

r^{2} = - 18 r

What are the solutions to the equation 0.25x^2-2x+3=0 ?
The solutions to the equation 0.25x^2-2x+3=0 are x=6,x=2
Find the zeros of 0.25x^2-2x+3=0
The zeros of 0.25x^2-2x+3=0 are x=6,x=2