What are the solutions to the equation 125a=5a^2 ?

The solutions to the equation 125a=5a^2 are a=0,a=25

Find the zeros of 125a=5a^2

The zeros of 125a=5a^2 are a=0,a=25

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125 a = 5 a^{2}

a = 0, a = 25

Solution steps

125 a = 5 a^{2}

Move

5 a^{2}

to the left side

125 a - 5 a^{2} = 0

Factor

125 a - 5 a^{2} : - 5 a (a - 25)

- 5 a (a - 25) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a = 0 or a - 25 = 0

Solve

a - 25 = 0 : a = 25

The solutions to the quadratic equation are:

a = 0, a = 25

r^{2} = - 18 r

- 0.5 = - 0.001 x^{2} + 0.06 x + 37.1

- 30 + 13 x + 3 x^{2} = 0

x^{2} + x^{2} + 9 x = 56

x^{2} + 11 x - 9 = 0

What are the solutions to the equation 125a=5a^2 ?
The solutions to the equation 125a=5a^2 are a=0,a=25
Find the zeros of 125a=5a^2
The zeros of 125a=5a^2 are a=0,a=25