What are the solutions to the equation r^2=-18r ?

The solutions to the equation r^2=-18r are r=0,r=-18

Find the zeros of r^2=-18r

The zeros of r^2=-18r are r=0,r=-18

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r^{2} = - 18 r

r = 0, r = - 18

Solution steps

r^{2} = - 18 r

Move

18 r

to the left side

r^{2} + 18 r = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 0 = 18

r_{1, 2} = \frac{- 18 \pm 18}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 18 + 18}{2 \cdot 1}, r_{2} = \frac{- 18 - 18}{2 \cdot 1}

r = \frac{- 18 + 18}{2 \cdot 1} : 0

r = \frac{- 18 - 18}{2 \cdot 1} : - 18

The solutions to the quadratic equation are:

r = 0, r = - 18

- 0.5 = - 0.001 x^{2} + 0.06 x + 37.1

- 30 + 13 x + 3 x^{2} = 0

x^{2} + x^{2} + 9 x = 56

x^{2} + 11 x - 9 = 0

R^{2} = (4)^{2} + (3)^{2}

What are the solutions to the equation r^2=-18r ?
The solutions to the equation r^2=-18r are r=0,r=-18
Find the zeros of r^2=-18r
The zeros of r^2=-18r are r=0,r=-18