What are the solutions to the equation x^2+x^2+9x=56 ?

The solutions to the equation x^2+x^2+9x=56 are x= 7/2 ,x=-8

Find the zeros of x^2+x^2+9x=56

The zeros of x^2+x^2+9x=56 are x= 7/2 ,x=-8

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x^{2} + x^{2} + 9 x = 56

x = \frac{7}{2}, x = - 8

Decimal Notation

x = 3.5, x = - 8

Solution steps

x^{2} + x^{2} + 9 x = 56

Refine

2 x^{2} + 9 x = 56

Move

56

to the left side

2 x^{2} + 9 x - 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 ( - 56 )}{2 \cdot 2}

9^{2} - 4 \cdot 2 (- 56) = 23

x_{1, 2} = \frac{- 9 \pm 23}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 9 + 23}{2 \cdot 2}, x_{2} = \frac{- 9 - 23}{2 \cdot 2}

x = \frac{- 9 + 23}{2 \cdot 2} : \frac{7}{2}

x = \frac{- 9 - 23}{2 \cdot 2} : - 8

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - 8

x^{2} + 11 x - 9 = 0

R^{2} = (4)^{2} + (3)^{2}

5 x^{2} = 10 x - 4

\frac{1}{8} - t^{2} = 0

2 x^{2} + 3 x = 77

What are the solutions to the equation x^2+x^2+9x=56 ?
The solutions to the equation x^2+x^2+9x=56 are x= 7/2 ,x=-8
Find the zeros of x^2+x^2+9x=56
The zeros of x^2+x^2+9x=56 are x= 7/2 ,x=-8