What are the solutions to the equation 4x^2+4x=33 ?

The solutions to the equation 4x^2+4x=33 are x=(-1+sqrt(34))/2 ,x=-(1+sqrt(34))/2

Find the zeros of 4x^2+4x=33

The zeros of 4x^2+4x=33 are x=(-1+sqrt(34))/2 ,x=-(1+sqrt(34))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 4 x = 33

x = \frac{- 1 + 34}{2}, x = - \frac{1 + 34}{2}

Decimal Notation

x = 2.41547 \dots, x = - 3.41547 \dots

Solution steps

4 x^{2} + 4 x = 33

Move

33

to the left side

4 x^{2} + 4 x - 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 33 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 33) = 434

x_{1, 2} = \frac{- 4 \pm 4 34}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 4 34}{2 \cdot 4}, x_{2} = \frac{- 4 - 4 34}{2 \cdot 4}

x = \frac{- 4 + 4 34}{2 \cdot 4} : \frac{- 1 + 34}{2}

x = \frac{- 4 - 4 34}{2 \cdot 4} : - \frac{1 + 34}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 34}{2}, x = - \frac{1 + 34}{2}

x^{2} + (- 8) x + 15 = 0

0 = 2 x^{2} + 6 x - 3

4 x^{2} = - 32

4 x^{2} = 225

x^{2} - 10 x + 30 = 9

What are the solutions to the equation 4x^2+4x=33 ?
The solutions to the equation 4x^2+4x=33 are x=(-1+sqrt(34))/2 ,x=-(1+sqrt(34))/2
Find the zeros of 4x^2+4x=33
The zeros of 4x^2+4x=33 are x=(-1+sqrt(34))/2 ,x=-(1+sqrt(34))/2