What are the solutions to the equation z^2+14z-1=0 ?

The solutions to the equation z^2+14z-1=0 are z=-7+5sqrt(2),z=-7-5sqrt(2)

Find the zeros of z^2+14z-1=0

The zeros of z^2+14z-1=0 are z=-7+5sqrt(2),z=-7-5sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

z^{2} + 14 z - 1 = 0

z = - 7 + 52, z = - 7 - 52

Decimal Notation

z = 0.07106 \dots, z = - 14.07106 \dots

Solution steps

z^{2} + 14 z - 1 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 1) = 102

z_{1, 2} = \frac{- 14 \pm 10 2}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 14 + 10 2}{2 \cdot 1}, z_{2} = \frac{- 14 - 10 2}{2 \cdot 1}

z = \frac{- 14 + 10 2}{2 \cdot 1} : - 7 + 52

z = \frac{- 14 - 10 2}{2 \cdot 1} : - 7 - 52

The solutions to the quadratic equation are:

z = - 7 + 52, z = - 7 - 52

- 3 x (4 x + 2) = 2 x + 1

4 x^{2} - 72 x = - 68

- 5 x - x^{2} = 84

(6 - x) (2 - x) + 5 = 0

6 x^{2} + 6 x - 13 = 0

What are the solutions to the equation z^2+14z-1=0 ?
The solutions to the equation z^2+14z-1=0 are z=-7+5sqrt(2),z=-7-5sqrt(2)
Find the zeros of z^2+14z-1=0
The zeros of z^2+14z-1=0 are z=-7+5sqrt(2),z=-7-5sqrt(2)