What are the solutions to the equation f^2-3f+2=0 ?

The solutions to the equation f^2-3f+2=0 are f=2,f=1

Find the zeros of f^2-3f+2=0

The zeros of f^2-3f+2=0 are f=2,f=1

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f^{2} - 3 f + 2 = 0

f = 2, f = 1

Solution steps

f^{2} - 3 f + 2 = 0

Solve with the quadratic formula

f_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 2 = 1

f_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 \cdot 1}

Separate the solutions

f_{1} = \frac{- ( - 3 ) + 1}{2 \cdot 1}, f_{2} = \frac{- ( - 3 ) - 1}{2 \cdot 1}

f = \frac{- ( - 3 ) + 1}{2 \cdot 1} : 2

f = \frac{- ( - 3 ) - 1}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

f = 2, f = 1

2 x^{2} + 5 = 103

a x^{2} + 2 x + 6 = 0

\frac{1}{2} (x + 2)^{2} + 5 = 3

0 = 2 x^{2} - 11 x - 40

a, (a - b)^{2} = 9

What are the solutions to the equation f^2-3f+2=0 ?
The solutions to the equation f^2-3f+2=0 are f=2,f=1
Find the zeros of f^2-3f+2=0
The zeros of f^2-3f+2=0 are f=2,f=1