What are the solutions to the equation 1/2 (x+2)^2+5=3 ?

The solutions to the equation 1/2 (x+2)^2+5=3 are x=2i-2,x=-2i-2

Find the zeros of 1/2 (x+2)^2+5=3

The zeros of 1/2 (x+2)^2+5=3 are x=2i-2,x=-2i-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{1}{2} (x + 2)^{2} + 5 = 3

x = 2 i - 2, x = - 2 i - 2

Solution steps

\frac{1}{2} (x + 2)^{2} + 5 = 3

Move

5

to the right side

\frac{1}{2} (x + 2)^{2} = - 2

Multiply both sides by

2

(x + 2)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = - 4 : x = 2 i - 2

Solve

x + 2 = - - 4 : x = - 2 i - 2

The solutions to the quadratic equation are:

x = 2 i - 2, x = - 2 i - 2

0 = 2 x^{2} - 11 x - 40

a, (a - b)^{2} = 9

x^{2} + 4 x + 4 = 36

x, 4 x^{2} + k x + 16 = 0

4 x^{2} + 36 x + 9 = 0

What are the solutions to the equation 1/2 (x+2)^2+5=3 ?
The solutions to the equation 1/2 (x+2)^2+5=3 are x=2i-2,x=-2i-2
Find the zeros of 1/2 (x+2)^2+5=3
The zeros of 1/2 (x+2)^2+5=3 are x=2i-2,x=-2i-2