What are the solutions to the equation 3(x-2)^2+48=0 ?

The solutions to the equation 3(x-2)^2+48=0 are x=4i+2,x=-4i+2

Find the zeros of 3(x-2)^2+48=0

The zeros of 3(x-2)^2+48=0 are x=4i+2,x=-4i+2

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3 (x - 2)^{2} + 48 = 0

x = 4 i + 2, x = - 4 i + 2

Solution steps

3 (x - 2)^{2} + 48 = 0

Move

48

to the right side

3 (x - 2)^{2} = - 48

Divide both sides by

3

(x - 2)^{2} = - 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = - 16 : x = 4 i + 2

Solve

x - 2 = - - 16 : x = - 4 i + 2

The solutions to the quadratic equation are:

x = 4 i + 2, x = - 4 i + 2

a^{2} - 10 a + 16 = 0

7 r^{2} = - 49 r

y, \frac{y ( y - k )}{z} = t

c^{2} - 14 c + 49 = 0

x^{2} - 9 x + 4 = 24

What are the solutions to the equation 3(x-2)^2+48=0 ?
The solutions to the equation 3(x-2)^2+48=0 are x=4i+2,x=-4i+2
Find the zeros of 3(x-2)^2+48=0
The zeros of 3(x-2)^2+48=0 are x=4i+2,x=-4i+2