What are the solutions to the equation 2u^2+5u-3=0 ?

The solutions to the equation 2u^2+5u-3=0 are u= 1/2 ,u=-3

Find the zeros of 2u^2+5u-3=0

The zeros of 2u^2+5u-3=0 are u= 1/2 ,u=-3

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2 u^{2} + 5 u - 3 = 0

u = \frac{1}{2}, u = - 3

Decimal Notation

u = 0.5, u = - 3

Solution steps

2 u^{2} + 5 u - 3 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 3) = 7

u_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 2}

Separate the solutions

u_{1} = \frac{- 5 + 7}{2 \cdot 2}, u_{2} = \frac{- 5 - 7}{2 \cdot 2}

u = \frac{- 5 + 7}{2 \cdot 2} : \frac{1}{2}

u = \frac{- 5 - 7}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

u = \frac{1}{2}, u = - 3

2 x^{2} + 14 x = 16

n^{2} - n = 6

x^{2} - 14 x - 4 = 0

54 = 0.04 x^{2} + 0.2 x + 12

x^{2} - 6 x - 2

What are the solutions to the equation 2u^2+5u-3=0 ?
The solutions to the equation 2u^2+5u-3=0 are u= 1/2 ,u=-3
Find the zeros of 2u^2+5u-3=0
The zeros of 2u^2+5u-3=0 are u= 1/2 ,u=-3