What are the solutions to the equation -4.9t^2+5t+21=0 ?

The solutions to the equation -4.9t^2+5t+21=0 are t=-(-25+sqrt(10915))/(49),t=(25+sqrt(10915))/(49)

Find the zeros of -4.9t^2+5t+21=0

The zeros of -4.9t^2+5t+21=0 are t=-(-25+sqrt(10915))/(49),t=(25+sqrt(10915))/(49)

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- 4.9 t^{2} + 5 t + 21 = 0

t = - \frac{- 25 + 10915}{49}, t = \frac{25 + 10915}{49}

Decimal Notation

t = - 1.62193 \dots, t = 2.64234 \dots

Solution steps

- 4.9 t^{2} + 5 t + 21 = 0

Multiply both sides by

10

- 49 t^{2} + 50 t + 210 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 ( - 49 ) \cdot 210}{2 ( - 49 )}

5 0^{2} - 4 (- 49) \cdot 210 = 210915

t_{1, 2} = \frac{- 50 \pm 2 10915}{2 ( - 49 )}

Separate the solutions

t_{1} = \frac{- 50 + 2 10915}{2 ( - 49 )}, t_{2} = \frac{- 50 - 2 10915}{2 ( - 49 )}

t = \frac{- 50 + 2 10915}{2 ( - 49 )} : - \frac{- 25 + 10915}{49}

t = \frac{- 50 - 2 10915}{2 ( - 49 )} : \frac{25 + 10915}{49}

The solutions to the quadratic equation are:

t = - \frac{- 25 + 10915}{49}, t = \frac{25 + 10915}{49}

2 x (x + 2) = 4

(3 x - 6)^{2} + 2 (3 x - 6) - 8 = 0

7 - 5 x = 3 x^{2}

2 (x + 6)^{2} = 8

- x^{2} + 18 x - 22 = - 2

What are the solutions to the equation -4.9t^2+5t+21=0 ?
The solutions to the equation -4.9t^2+5t+21=0 are t=-(-25+sqrt(10915))/(49),t=(25+sqrt(10915))/(49)
Find the zeros of -4.9t^2+5t+21=0
The zeros of -4.9t^2+5t+21=0 are t=-(-25+sqrt(10915))/(49),t=(25+sqrt(10915))/(49)