What are the solutions to the equation 0=2(x-1)^2-3 ?

The solutions to the equation 0=2(x-1)^2-3 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1

Find the zeros of 0=2(x-1)^2-3

The zeros of 0=2(x-1)^2-3 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1

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0 = 2 (x - 1)^{2} - 3

x = \frac{3}{2} + 1, x = - \frac{3}{2} + 1

Decimal Notation

x = 2.22474 \dots, x = - 0.22474 \dots

Solution steps

0 = 2 (x - 1)^{2} - 3

Switch sides

2 (x - 1)^{2} - 3 = 0

Move

3

to the right side

2 (x - 1)^{2} = 3

Divide both sides by

2

(x - 1)^{2} = \frac{3}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = \frac{3}{2} : x = \frac{3}{2} + 1

Solve

x - 1 = - \frac{3}{2} : x = - \frac{3}{2} + 1

The solutions to the quadratic equation are:

x = \frac{3}{2} + 1, x = - \frac{3}{2} + 1

x, x^{2} - 14 x y + y^{2} = 14

3 x^{2} = 63 x + 6

2 x^{2} + x - \frac{1}{2} = 0

6^{2} + 1 1^{2} = c^{2}

\frac{3 x ^{2}}{2} = 150

What are the solutions to the equation 0=2(x-1)^2-3 ?
The solutions to the equation 0=2(x-1)^2-3 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1
Find the zeros of 0=2(x-1)^2-3
The zeros of 0=2(x-1)^2-3 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1