What are the solutions to the equation -5x^2+25x=-120 ?

The solutions to the equation -5x^2+25x=-120 are x=-3,x=8

Find the zeros of -5x^2+25x=-120

The zeros of -5x^2+25x=-120 are x=-3,x=8

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- 5 x^{2} + 25 x = - 120

x = - 3, x = 8

Solution steps

- 5 x^{2} + 25 x = - 120

Move

120

to the left side

- 5 x^{2} + 25 x + 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 ( - 5 ) \cdot 120}{2 ( - 5 )}

2 5^{2} - 4 (- 5) \cdot 120 = 55

x_{1, 2} = \frac{- 25 \pm 55}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 25 + 55}{2 ( - 5 )}, x_{2} = \frac{- 25 - 55}{2 ( - 5 )}

x = \frac{- 25 + 55}{2 ( - 5 )} : - 3

x = \frac{- 25 - 55}{2 ( - 5 )} : 8

The solutions to the quadratic equation are:

x = - 3, x = 8

r^{2} - 4 r - 91 + 7 = 0

3 x^{2} - 5 x - 16 = 0

4 x^{2} - 28 x + 49

m^{2} - 5 m - 14 = 0

5 n^{2} - 14 = - 6

What are the solutions to the equation -5x^2+25x=-120 ?
The solutions to the equation -5x^2+25x=-120 are x=-3,x=8
Find the zeros of -5x^2+25x=-120
The zeros of -5x^2+25x=-120 are x=-3,x=8