What are the solutions to the equation x^2+8x=-6 ?

The solutions to the equation x^2+8x=-6 are x=-4+sqrt(10),x=-4-sqrt(10)

Find the zeros of x^2+8x=-6

The zeros of x^2+8x=-6 are x=-4+sqrt(10),x=-4-sqrt(10)

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x^{2} + 8 x = - 6

x = - 4 + 10, x = - 4 - 10

Decimal Notation

x = - 0.83772 \dots, x = - 7.16227 \dots

Solution steps

x^{2} + 8 x = - 6

Move

6

to the left side

x^{2} + 8 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 6 = 210

x_{1, 2} = \frac{- 8 \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 10}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 10}{2 \cdot 1}

x = \frac{- 8 + 2 10}{2 \cdot 1} : - 4 + 10

x = \frac{- 8 - 2 10}{2 \cdot 1} : - 4 - 10

The solutions to the quadratic equation are:

x = - 4 + 10, x = - 4 - 10

- \frac{q ^{2}}{9} + 3 q - 2 = 0

\frac{2 x ^{2} - 3}{4} = 5

x, 4 x^{2} + k x + 9 = 0

15 - x^{2} = 0

7 x^{2} + 58 x + 63 = 0

What are the solutions to the equation x^2+8x=-6 ?
The solutions to the equation x^2+8x=-6 are x=-4+sqrt(10),x=-4-sqrt(10)
Find the zeros of x^2+8x=-6
The zeros of x^2+8x=-6 are x=-4+sqrt(10),x=-4-sqrt(10)