What are the solutions to the equation 28x^2+3x-18=0 ?

The solutions to the equation 28x^2+3x-18=0 are x= 3/4 ,x=-6/7

Find the zeros of 28x^2+3x-18=0

The zeros of 28x^2+3x-18=0 are x= 3/4 ,x=-6/7

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28 x^{2} + 3 x - 18 = 0

x = \frac{3}{4}, x = - \frac{6}{7}

Decimal Notation

x = 0.75, x = - 0.85714 \dots

Solution steps

28 x^{2} + 3 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 28 ( - 18 )}{2 \cdot 28}

3^{2} - 4 \cdot 28 (- 18) = 45

x_{1, 2} = \frac{- 3 \pm 45}{2 \cdot 28}

Separate the solutions

x_{1} = \frac{- 3 + 45}{2 \cdot 28}, x_{2} = \frac{- 3 - 45}{2 \cdot 28}

x = \frac{- 3 + 45}{2 \cdot 28} : \frac{3}{4}

x = \frac{- 3 - 45}{2 \cdot 28} : - \frac{6}{7}

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = - \frac{6}{7}

3 x^{2} - x - 2 = 1

5 x^{2} + 20 x - 85 = 0

9 x^{2} - c^{2} = 0

0.0169 = c^{2}

x, x^{2} + 1 = y^{3} - 1

What are the solutions to the equation 28x^2+3x-18=0 ?
The solutions to the equation 28x^2+3x-18=0 are x= 3/4 ,x=-6/7
Find the zeros of 28x^2+3x-18=0
The zeros of 28x^2+3x-18=0 are x= 3/4 ,x=-6/7