What are the solutions to the equation 6x^2+24x=-10 ?

The solutions to the equation 6x^2+24x=-10 are x=(-6+sqrt(21))/3 ,x=-(6+sqrt(21))/3

Find the zeros of 6x^2+24x=-10

The zeros of 6x^2+24x=-10 are x=(-6+sqrt(21))/3 ,x=-(6+sqrt(21))/3

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6 x^{2} + 24 x = - 10

x = \frac{- 6 + 21}{3}, x = - \frac{6 + 21}{3}

Decimal Notation

x = - 0.47247 \dots, x = - 3.52752 \dots

Solution steps

6 x^{2} + 24 x = - 10

Move

10

to the left side

6 x^{2} + 24 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 6 \cdot 10}{2 \cdot 6}

2 4^{2} - 4 \cdot 6 \cdot 10 = 421

x_{1, 2} = \frac{- 24 \pm 4 21}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 24 + 4 21}{2 \cdot 6}, x_{2} = \frac{- 24 - 4 21}{2 \cdot 6}

x = \frac{- 24 + 4 21}{2 \cdot 6} : \frac{- 6 + 21}{3}

x = \frac{- 24 - 4 21}{2 \cdot 6} : - \frac{6 + 21}{3}

The solutions to the quadratic equation are:

x = \frac{- 6 + 21}{3}, x = - \frac{6 + 21}{3}

x (6 x + 7) = 3

x^{2} + 32 x + 116 = 12 x

2 x^{2} + 2 x + 32 = 0

x^{2} - 4 x + 4 = - 2 + 4

y, - 16 y^{2} + 9 z^{2} = 0

What are the solutions to the equation 6x^2+24x=-10 ?
The solutions to the equation 6x^2+24x=-10 are x=(-6+sqrt(21))/3 ,x=-(6+sqrt(21))/3
Find the zeros of 6x^2+24x=-10
The zeros of 6x^2+24x=-10 are x=(-6+sqrt(21))/3 ,x=-(6+sqrt(21))/3