What are the solutions to the equation x^2-4x+4=-2+4 ?

The solutions to the equation x^2-4x+4=-2+4 are x=2+sqrt(2),x=2-sqrt(2)

Find the zeros of x^2-4x+4=-2+4

The zeros of x^2-4x+4=-2+4 are x=2+sqrt(2),x=2-sqrt(2)

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x^{2} - 4 x + 4 = - 2 + 4

x = 2 + 2, x = 2 - 2

Decimal Notation

x = 3.41421 \dots, x = 0.58578 \dots

Solution steps

x^{2} - 4 x + 4 = - 2 + 4

Refine

x^{2} - 4 x + 4 = 2

Move

2

to the left side

x^{2} - 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 2 = 22

x_{1, 2} = \frac{- ( - 4 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 2}{2 \cdot 1} : 2 + 2

x = \frac{- ( - 4 ) - 2 2}{2 \cdot 1} : 2 - 2

The solutions to the quadratic equation are:

x = 2 + 2, x = 2 - 2

y, - 16 y^{2} + 9 z^{2} = 0

125 x^{2} + 50 x - 5 = 0

t, x = t^{2} + t

0 = - 6 c^{2} + 30 c + 300

1 7^{2} = x^{2} + 5^{2}

What are the solutions to the equation x^2-4x+4=-2+4 ?
The solutions to the equation x^2-4x+4=-2+4 are x=2+sqrt(2),x=2-sqrt(2)
Find the zeros of x^2-4x+4=-2+4
The zeros of x^2-4x+4=-2+4 are x=2+sqrt(2),x=2-sqrt(2)