What are the solutions to the equation 2x^2+2x+32=0 ?

The solutions to the equation 2x^2+2x+32=0 are x=-1/2+i(3sqrt(7))/2 ,x=-1/2-i(3sqrt(7))/2

Find the zeros of 2x^2+2x+32=0

The zeros of 2x^2+2x+32=0 are x=-1/2+i(3sqrt(7))/2 ,x=-1/2-i(3sqrt(7))/2

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2 x^{2} + 2 x + 32 = 0

x = - \frac{1}{2} + i \frac{3 7}{2}, x = - \frac{1}{2} - i \frac{3 7}{2}

Solution steps

2 x^{2} + 2 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 \cdot 32}{2 \cdot 2}

Simplify

2^{2} - 4 \cdot 2 \cdot 32 : 67 i

x_{1, 2} = \frac{- 2 \pm 6 7 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 6 7 i}{2 \cdot 2}, x_{2} = \frac{- 2 - 6 7 i}{2 \cdot 2}

x = \frac{- 2 + 6 7 i}{2 \cdot 2} : - \frac{1}{2} + i \frac{3 7}{2}

x = \frac{- 2 - 6 7 i}{2 \cdot 2} : - \frac{1}{2} - i \frac{3 7}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{3 7}{2}, x = - \frac{1}{2} - i \frac{3 7}{2}

x^{2} - 4 x + 4 = - 2 + 4

y, - 16 y^{2} + 9 z^{2} = 0

125 x^{2} + 50 x - 5 = 0

t, x = t^{2} + t

0 = - 6 c^{2} + 30 c + 300

What are the solutions to the equation 2x^2+2x+32=0 ?
The solutions to the equation 2x^2+2x+32=0 are x=-1/2+i(3sqrt(7))/2 ,x=-1/2-i(3sqrt(7))/2
Find the zeros of 2x^2+2x+32=0
The zeros of 2x^2+2x+32=0 are x=-1/2+i(3sqrt(7))/2 ,x=-1/2-i(3sqrt(7))/2