What are the solutions to the equation 4s^2+9=125 ?

The solutions to the equation 4s^2+9=125 are s=sqrt(29),s=-sqrt(29)

Find the zeros of 4s^2+9=125

The zeros of 4s^2+9=125 are s=sqrt(29),s=-sqrt(29)

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4 s^{2} + 9 = 125

s = 29, s = - 29

Decimal Notation

s = 5.38516 \dots, s = - 5.38516 \dots

Solution steps

4 s^{2} + 9 = 125

Move

9

to the right side

4 s^{2} = 116

Divide both sides by

4

s^{2} = 29

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

s = 29, s = - 29

5 x^{2} = 4 - 2 x

- 4 = - 4 x^{2} - 6 x

2 x^{2} - \frac{1}{32} = 0

t, 7 = 16 - 9.8 t^{2}

x^{2} + 3 x - 15 = - 4

What are the solutions to the equation 4s^2+9=125 ?
The solutions to the equation 4s^2+9=125 are s=sqrt(29),s=-sqrt(29)
Find the zeros of 4s^2+9=125
The zeros of 4s^2+9=125 are s=sqrt(29),s=-sqrt(29)