What are the solutions to the equation 22=-2.7t^2+30t+6.5 ?

The solutions to the equation 22=-2.7t^2+30t+6.5 are t=(50-sqrt(2035))/9 ,t=(50+sqrt(2035))/9

Find the zeros of 22=-2.7t^2+30t+6.5

The zeros of 22=-2.7t^2+30t+6.5 are t=(50-sqrt(2035))/9 ,t=(50+sqrt(2035))/9

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22 = - 2.7 t^{2} + 30 t + 6.5

t = \frac{50 - 2035}{9}, t = \frac{50 + 2035}{9}

Decimal Notation

t = 0.54322 \dots, t = 10.56788 \dots

Solution steps

22 = - 2.7 t^{2} + 30 t + 6.5

Multiply both sides by

10

220 = - 27 t^{2} + 300 t + 65

Switch sides

- 27 t^{2} + 300 t + 65 = 220

Move

220

to the left side

- 27 t^{2} + 300 t - 155 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 300 \pm 30 0 ^{2} - 4 ( - 27 ) ( - 155 )}{2 ( - 27 )}

30 0^{2} - 4 (- 27) (- 155) = 62035

t_{1, 2} = \frac{- 300 \pm 6 2035}{2 ( - 27 )}

Separate the solutions

t_{1} = \frac{- 300 + 6 2035}{2 ( - 27 )}, t_{2} = \frac{- 300 - 6 2035}{2 ( - 27 )}

t = \frac{- 300 + 6 2035}{2 ( - 27 )} : \frac{50 - 2035}{9}

t = \frac{- 300 - 6 2035}{2 ( - 27 )} : \frac{50 + 2035}{9}

The solutions to the quadratic equation are:

t = \frac{50 - 2035}{9}, t = \frac{50 + 2035}{9}

- 9 x^{2} + 4 x = 0

y, 0 = 3 y - 2 x y - 3 y^{2}

x, a x^{2} + b x = - c

4 x^{2} + 10 x - 15 = 0

x^{2} - 10 \cdot x + 24 = 0

What are the solutions to the equation 22=-2.7t^2+30t+6.5 ?
The solutions to the equation 22=-2.7t^2+30t+6.5 are t=(50-sqrt(2035))/9 ,t=(50+sqrt(2035))/9
Find the zeros of 22=-2.7t^2+30t+6.5
The zeros of 22=-2.7t^2+30t+6.5 are t=(50-sqrt(2035))/9 ,t=(50+sqrt(2035))/9