What are the solutions to the equation 1/2 x^2+2x+2=0 ?

The solutions to the equation 1/2 x^2+2x+2=0 are x=-2

Find the zeros of 1/2 x^2+2x+2=0

The zeros of 1/2 x^2+2x+2=0 are x=-2

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\frac{1}{2} x^{2} + 2 x + 2 = 0

x = - 2

Solution steps

\frac{1}{2} x^{2} + 2 x + 2 = 0

Multiply both sides by

2

x^{2} + 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

x = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

2 k^{2} + k - 7 = 0

10 a^{2} + 5 a = 15

x^{2} - 4 x + 96 = 0

5 x = x^{2} + 1

16 t^{2} - 128 t + 192 = 0

What are the solutions to the equation 1/2 x^2+2x+2=0 ?
The solutions to the equation 1/2 x^2+2x+2=0 are x=-2
Find the zeros of 1/2 x^2+2x+2=0
The zeros of 1/2 x^2+2x+2=0 are x=-2