What are the solutions to the equation 2k^2+k-7=0 ?

The solutions to the equation 2k^2+k-7=0 are k=(-1+sqrt(57))/4 ,k=(-1-sqrt(57))/4

Find the zeros of 2k^2+k-7=0

The zeros of 2k^2+k-7=0 are k=(-1+sqrt(57))/4 ,k=(-1-sqrt(57))/4

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2 k^{2} + k - 7 = 0

k = \frac{- 1 + 57}{4}, k = \frac{- 1 - 57}{4}

Decimal Notation

k = 1.63745 \dots, k = - 2.13745 \dots

Solution steps

2 k^{2} + k - 7 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 7 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 7) = 57

k_{1, 2} = \frac{- 1 \pm 57}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- 1 + 57}{2 \cdot 2}, k_{2} = \frac{- 1 - 57}{2 \cdot 2}

k = \frac{- 1 + 57}{2 \cdot 2} : \frac{- 1 + 57}{4}

k = \frac{- 1 - 57}{2 \cdot 2} : \frac{- 1 - 57}{4}

The solutions to the quadratic equation are:

k = \frac{- 1 + 57}{4}, k = \frac{- 1 - 57}{4}

10 a^{2} + 5 a = 15

x^{2} - 4 x + 96 = 0

5 x = x^{2} + 1

16 t^{2} - 128 t + 192 = 0

12 y^{2} + 55 y + 63 = 0

What are the solutions to the equation 2k^2+k-7=0 ?
The solutions to the equation 2k^2+k-7=0 are k=(-1+sqrt(57))/4 ,k=(-1-sqrt(57))/4
Find the zeros of 2k^2+k-7=0
The zeros of 2k^2+k-7=0 are k=(-1+sqrt(57))/4 ,k=(-1-sqrt(57))/4