What are the solutions to the equation 8x^2+189x-72=0 ?

The solutions to the equation 8x^2+189x-72=0 are x= 3/8 ,x=-24

Find the zeros of 8x^2+189x-72=0

The zeros of 8x^2+189x-72=0 are x= 3/8 ,x=-24

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8 x^{2} + 189 x - 72 = 0

x = \frac{3}{8}, x = - 24

Decimal Notation

x = 0.375, x = - 24

Solution steps

8 x^{2} + 189 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 189 \pm 18 9 ^{2} - 4 \cdot 8 ( - 72 )}{2 \cdot 8}

18 9^{2} - 4 \cdot 8 (- 72) = 195

x_{1, 2} = \frac{- 189 \pm 195}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 189 + 195}{2 \cdot 8}, x_{2} = \frac{- 189 - 195}{2 \cdot 8}

x = \frac{- 189 + 195}{2 \cdot 8} : \frac{3}{8}

x = \frac{- 189 - 195}{2 \cdot 8} : - 24

The solutions to the quadratic equation are:

x = \frac{3}{8}, x = - 24

9 x^{2} + 7 x + 49 = 0

13 x - 3 x^{2} = 0

x^{2} = 242

15 x - 10 = 6 x - (x x^{2}) + (- x + 3)

13 x^{2} - 16 x = 4

What are the solutions to the equation 8x^2+189x-72=0 ?
The solutions to the equation 8x^2+189x-72=0 are x= 3/8 ,x=-24
Find the zeros of 8x^2+189x-72=0
The zeros of 8x^2+189x-72=0 are x= 3/8 ,x=-24