What are the solutions to the equation x(2x-4)=3(2x-4) ?

The solutions to the equation x(2x-4)=3(2x-4) are x=2,x=3

Find the zeros of x(2x-4)=3(2x-4)

The zeros of x(2x-4)=3(2x-4) are x=2,x=3

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x (2 x - 4) = 3 (2 x - 4)

x = 2, x = 3

Solution steps

x (2 x - 4) = 3 (2 x - 4)

Move

3 (2 x - 4)

to the left side

x (2 x - 4) - 3 (2 x - 4) = 0

Factor

x (2 x - 4) - 3 (2 x - 4) : 2 (x - 2) (x - 3)

2 (x - 2) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x - 3 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = 2, x = 3

x^{2} - (m + n) x + m \cdot n = 0

14 z^{2} - 51 z = 54

y^{2} - 6 y + 12 = 0

4 y^{2} - (4 - y^{2}) = 4

x^{2} - 0.011 x - 0.063 = 0

What are the solutions to the equation x(2x-4)=3(2x-4) ?
The solutions to the equation x(2x-4)=3(2x-4) are x=2,x=3
Find the zeros of x(2x-4)=3(2x-4)
The zeros of x(2x-4)=3(2x-4) are x=2,x=3