What are the solutions to the equation 4.9x^2+16.8x+7.6=0 ?

The solutions to the equation 4.9x^2+16.8x+7.6=0 are x=(2(sqrt(17)-6))/7 ,x=-(2(6+sqrt(17)))/7

Find the zeros of 4.9x^2+16.8x+7.6=0

The zeros of 4.9x^2+16.8x+7.6=0 are x=(2(sqrt(17)-6))/7 ,x=-(2(6+sqrt(17)))/7

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4.9 x^{2} + 16.8 x + 7.6 = 0

x = \frac{2 ( 17 - 6 )}{7}, x = - \frac{2 ( 6 + 17 )}{7}

Decimal Notation

x = - 0.53625 \dots, x = - 2.89231 \dots

Solution steps

4.9 x^{2} + 16.8 x + 7.6 = 0

Multiply both sides by

10

49 x^{2} + 168 x + 76 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 168 \pm 16 8 ^{2} - 4 \cdot 49 \cdot 76}{2 \cdot 49}

16 8^{2} - 4 \cdot 49 \cdot 76 = 2817

x_{1, 2} = \frac{- 168 \pm 28 17}{2 \cdot 49}

Separate the solutions

x_{1} = \frac{- 168 + 28 17}{2 \cdot 49}, x_{2} = \frac{- 168 - 28 17}{2 \cdot 49}

x = \frac{- 168 + 28 17}{2 \cdot 49} : \frac{2 ( 17 - 6 )}{7}

x = \frac{- 168 - 28 17}{2 \cdot 49} : - \frac{2 ( 6 + 17 )}{7}

The solutions to the quadratic equation are:

x = \frac{2 ( 17 - 6 )}{7}, x = - \frac{2 ( 6 + 17 )}{7}

- 4 = x^{2} + 5 x

x^{2} + 10 x = - 9

4 k^{2} - 2 = - 15

22 - 22 x = (5 x + 3) (x - 1)

- 4 n^{2} = 6 n + 16 - 5 n^{2}

What are the solutions to the equation 4.9x^2+16.8x+7.6=0 ?
The solutions to the equation 4.9x^2+16.8x+7.6=0 are x=(2(sqrt(17)-6))/7 ,x=-(2(6+sqrt(17)))/7
Find the zeros of 4.9x^2+16.8x+7.6=0
The zeros of 4.9x^2+16.8x+7.6=0 are x=(2(sqrt(17)-6))/7 ,x=-(2(6+sqrt(17)))/7