What are the solutions to the equation -6x^2-15x=-6 ?

The solutions to the equation -6x^2-15x=-6 are x=-(5+sqrt(41))/4 ,x=(sqrt(41)-5)/4

Find the zeros of -6x^2-15x=-6

The zeros of -6x^2-15x=-6 are x=-(5+sqrt(41))/4 ,x=(sqrt(41)-5)/4

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- 6 x^{2} - 15 x = - 6

x = - \frac{5 + 41}{4}, x = \frac{41 - 5}{4}

Decimal Notation

x = - 2.85078 \dots, x = 0.35078 \dots

Solution steps

- 6 x^{2} - 15 x = - 6

Move

6

to the left side

- 6 x^{2} - 15 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 ( - 6 ) \cdot 6}{2 ( - 6 )}

(- 15)^{2} - 4 (- 6) \cdot 6 = 341

x_{1, 2} = \frac{- ( - 15 ) \pm 3 41}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 3 41}{2 ( - 6 )}, x_{2} = \frac{- ( - 15 ) - 3 41}{2 ( - 6 )}

x = \frac{- ( - 15 ) + 3 41}{2 ( - 6 )} : - \frac{5 + 41}{4}

x = \frac{- ( - 15 ) - 3 41}{2 ( - 6 )} : \frac{41 - 5}{4}

The solutions to the quadratic equation are:

x = - \frac{5 + 41}{4}, x = \frac{41 - 5}{4}

15 x^{2} + 43 x + 8 = 0

(y - 2) (3 y + 5) = y (y - 2)

12 n^{2} - 18 n = 0

(2 - x) (3 - x) - 1 = 0

4 (x + 5) (4 + x) = 34

What are the solutions to the equation -6x^2-15x=-6 ?
The solutions to the equation -6x^2-15x=-6 are x=-(5+sqrt(41))/4 ,x=(sqrt(41)-5)/4
Find the zeros of -6x^2-15x=-6
The zeros of -6x^2-15x=-6 are x=-(5+sqrt(41))/4 ,x=(sqrt(41)-5)/4