What are the solutions to the equation -x^2+15x-50=0 ?

The solutions to the equation -x^2+15x-50=0 are x=5,x=10

Find the zeros of -x^2+15x-50=0

The zeros of -x^2+15x-50=0 are x=5,x=10

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- x^{2} + 15 x - 50 = 0

x = 5, x = 10

Solution steps

- x^{2} + 15 x - 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 ( - 1 ) ( - 50 )}{2 ( - 1 )}

1 5^{2} - 4 (- 1) (- 50) = 5

x_{1, 2} = \frac{- 15 \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 15 + 5}{2 ( - 1 )}, x_{2} = \frac{- 15 - 5}{2 ( - 1 )}

x = \frac{- 15 + 5}{2 ( - 1 )} : 5

x = \frac{- 15 - 5}{2 ( - 1 )} : 10

The solutions to the quadratic equation are:

x = 5, x = 10

- 4 x^{2} + 11 x - 275 = 0

x^{2} - 2 x + 2 = x + 2

3 x^{2} + 12 x - 24 = 0

- 5 x^{2} - 9 x + 4 = 0

4 t^{2} + 12 t - 17 = 0

What are the solutions to the equation -x^2+15x-50=0 ?
The solutions to the equation -x^2+15x-50=0 are x=5,x=10
Find the zeros of -x^2+15x-50=0
The zeros of -x^2+15x-50=0 are x=5,x=10