What are the solutions to the equation -4x^2+11x-275=0 ?

The solutions to the equation -4x^2+11x-275=0 are x= 11/8-i(sqrt(4279))/8 ,x= 11/8+i(sqrt(4279))/8

Find the zeros of -4x^2+11x-275=0

The zeros of -4x^2+11x-275=0 are x= 11/8-i(sqrt(4279))/8 ,x= 11/8+i(sqrt(4279))/8

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- 4 x^{2} + 11 x - 275 = 0

x = \frac{11}{8} - i \frac{4279}{8}, x = \frac{11}{8} + i \frac{4279}{8}

Solution steps

- 4 x^{2} + 11 x - 275 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 ( - 4 ) ( - 275 )}{2 ( - 4 )}

Simplify

1 1^{2} - 4 (- 4) (- 275) : 4279 i

x_{1, 2} = \frac{- 11 \pm 4279 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 11 + 4279 i}{2 ( - 4 )}, x_{2} = \frac{- 11 - 4279 i}{2 ( - 4 )}

x = \frac{- 11 + 4279 i}{2 ( - 4 )} : \frac{11}{8} - i \frac{4279}{8}

x = \frac{- 11 - 4279 i}{2 ( - 4 )} : \frac{11}{8} + i \frac{4279}{8}

The solutions to the quadratic equation are:

x = \frac{11}{8} - i \frac{4279}{8}, x = \frac{11}{8} + i \frac{4279}{8}

x^{2} - 2 x + 2 = x + 2

3 x^{2} + 12 x - 24 = 0

- 5 x^{2} - 9 x + 4 = 0

4 t^{2} + 12 t - 17 = 0

x^{2} - 9 = 0

What are the solutions to the equation -4x^2+11x-275=0 ?
The solutions to the equation -4x^2+11x-275=0 are x= 11/8-i(sqrt(4279))/8 ,x= 11/8+i(sqrt(4279))/8
Find the zeros of -4x^2+11x-275=0
The zeros of -4x^2+11x-275=0 are x= 11/8-i(sqrt(4279))/8 ,x= 11/8+i(sqrt(4279))/8