What are the solutions to the equation -3x^2+3x+1=0 ?

The solutions to the equation -3x^2+3x+1=0 are x=-(-3+sqrt(21))/6 ,x=(3+sqrt(21))/6

Find the zeros of -3x^2+3x+1=0

The zeros of -3x^2+3x+1=0 are x=-(-3+sqrt(21))/6 ,x=(3+sqrt(21))/6

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- 3 x^{2} + 3 x + 1 = 0

x = - \frac{- 3 + 21}{6}, x = \frac{3 + 21}{6}

Decimal Notation

x = - 0.26376 \dots, x = 1.26376 \dots

Solution steps

- 3 x^{2} + 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 3 ) \cdot 1}{2 ( - 3 )}

3^{2} - 4 (- 3) \cdot 1 = 21

x_{1, 2} = \frac{- 3 \pm 21}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 3 + 21}{2 ( - 3 )}, x_{2} = \frac{- 3 - 21}{2 ( - 3 )}

x = \frac{- 3 + 21}{2 ( - 3 )} : - \frac{- 3 + 21}{6}

x = \frac{- 3 - 21}{2 ( - 3 )} : \frac{3 + 21}{6}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 21}{6}, x = \frac{3 + 21}{6}

7^{2} + x^{2} = 1 3^{2}

p^{2} + 0.8 p + 0.16 = 1

(x + 4)^{2} + (x - 3)^{2} = (x - 5)^{2}

z (z + 5) = - 6

0 = \frac{- 1}{500} (x - 100)^{2} + 20

What are the solutions to the equation -3x^2+3x+1=0 ?
The solutions to the equation -3x^2+3x+1=0 are x=-(-3+sqrt(21))/6 ,x=(3+sqrt(21))/6
Find the zeros of -3x^2+3x+1=0
The zeros of -3x^2+3x+1=0 are x=-(-3+sqrt(21))/6 ,x=(3+sqrt(21))/6