What are the solutions to the equation p^2+0.8p+0.16=1 ?

The solutions to the equation p^2+0.8p+0.16=1 are p= 3/5 ,p=-7/5

Find the zeros of p^2+0.8p+0.16=1

The zeros of p^2+0.8p+0.16=1 are p= 3/5 ,p=-7/5

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p^{2} + 0.8 p + 0.16 = 1

p = \frac{3}{5}, p = - \frac{7}{5}

Decimal Notation

p = 0.6, p = - 1.4

Solution steps

p^{2} + 0.8 p + 0.16 = 1

Multiply both sides by

100

100 p^{2} + 80 p + 16 = 100

Move

100

to the left side

100 p^{2} + 80 p - 84 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 \cdot 100 ( - 84 )}{2 \cdot 100}

8 0^{2} - 4 \cdot 100 (- 84) = 200

p_{1, 2} = \frac{- 80 \pm 200}{2 \cdot 100}

Separate the solutions

p_{1} = \frac{- 80 + 200}{2 \cdot 100}, p_{2} = \frac{- 80 - 200}{2 \cdot 100}

p = \frac{- 80 + 200}{2 \cdot 100} : \frac{3}{5}

p = \frac{- 80 - 200}{2 \cdot 100} : - \frac{7}{5}

The solutions to the quadratic equation are:

p = \frac{3}{5}, p = - \frac{7}{5}

(x + 4)^{2} + (x - 3)^{2} = (x - 5)^{2}

z (z + 5) = - 6

0 = \frac{- 1}{500} (x - 100)^{2} + 20

5 x^{2} + 2 = 37

a^{2} + 3 a - 1 = 0

What are the solutions to the equation p^2+0.8p+0.16=1 ?
The solutions to the equation p^2+0.8p+0.16=1 are p= 3/5 ,p=-7/5
Find the zeros of p^2+0.8p+0.16=1
The zeros of p^2+0.8p+0.16=1 are p= 3/5 ,p=-7/5