What are the solutions to the equation solvefor x,x(x-2y)=-y^2 ?

The solutions to the equation solvefor x,x(x-2y)=-y^2 are x=y

Find the zeros of solvefor x,x(x-2y)=-y^2

The zeros of solvefor x,x(x-2y)=-y^2 are x=y

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solve for

x, x (x - 2 y) = - y^{2}

x = y

Solution steps

x (x - 2 y) = - y^{2}

Expand

x (x - 2 y) : x^{2} - 2 x y

x^{2} - 2 x y = - y^{2}

Move

y^{2}

to the left side

x^{2} - 2 x y + y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 y x + y^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 y ) \pm ( - 2 y ) ^{2} - 4 \cdot 1 \cdot y ^{2}}{2 \cdot 1}

(- 2 y)^{2} - 4 \cdot 1 \cdot y^{2} = 0

x_{1, 2} = \frac{- ( - 2 y ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 2 y )}{2 \cdot 1}

Simplify

\frac{- ( - 2 y )}{2 \cdot 1} : y

x = y

The solution to the quadratic equation is:

x = y

n^{2} = - 89 + 18 n

- 3 x + 2 x + \frac{8}{4} = - x^{2}

(x + 5)^{2} - 200 = 25

t^{2} = 4 t - 4

x^{2} - x - 3 = 0

What are the solutions to the equation solvefor x,x(x-2y)=-y^2 ?
The solutions to the equation solvefor x,x(x-2y)=-y^2 are x=y
Find the zeros of solvefor x,x(x-2y)=-y^2
The zeros of solvefor x,x(x-2y)=-y^2 are x=y